A person travels from P to Q at a speed of 40 kmph and returns by increasing his speed by 50%. What is his average speed for the both the trips?

** Option:**

**A.**45 kmph

**B.**48 kmph

**C.**50 kmph

**D.**55 kmph

**Answer: B . 48 kmph**

** Justification:**

Speed on return trip = 150% of 40 = 60 kmph.

Therefore Average speed = [ (2 x 40 x 60 ) / (40 + 60)] km/hr = (4800/100) km/hr = 48 km/hr.