A person travels from P to Q at a speed of 40 kmph and returns by increasing his speed by 50%. What is his average speed for the both the trips?
Option:
A. 45 kmph
B. 48 kmph
C. 50 kmph
D. 55 kmph
Answer: B . 48 kmph
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Justification:
Speed on return trip = 150% of 40 = 60 kmph.
Therefore Average speed = [ (2 x 40 x 60 ) / (40 + 60)] km/hr = (4800/100) km/hr = 48 km/hr.
