60 men undertook to finish a work in 62 days. They finished $2/3$ of the work in 32 days. How many men are required to finish the remaining work ?
Option:
A. 32 men
B. 30 men
C. 36 men
D. 40 men
Answer: A . 32 men
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Justification:
Let $x$ be the number of men required to comlpete the work in time.
Here, 60 men have comletes $2/3$ of the work in 32 days.
We have to find how many men will complete the remaing $1/3$ of work in remaining 62 - 32 i.e. 30days.
| Men | Work | Days |
| 60 | 2/3 | 32 |
| x | 1/3 | 30 |
days 30:32 60:x Less days, more man
Work $2/3:1/3$ men : men Less work, Less man
Thus, x =${32 × {1/3} × 60}/ {30 ×{2/3}}$ = 32 men
Hence, 32 men will be required to complete remaining work.
