60 men undertook to finish a work in 62 days. They finished $2/3$ of the work in 32 days. How many men are required to finish the remaining work ?

** Option:**

**A.**32 men

**B.**30 men

**C.**36 men

**D.**40 men

**Answer: A . 32 men**

** Justification:**

Let $x$ be the number of men required to comlpete the work in time.

Here, 60 men have comletes $2/3$ of the work in 32 days.

We have to find how many men will complete the remaing $1/3$ of work in remaining 62 - 32 i.e. 30days.

Men | Work | Days |

60 | 2/3 | 32 |

x | 1/3 | 30 |

days 30:32 60:x Less days, more man

Work $2/3:1/3$ men : men Less work, Less man

Thus, x =${32 × {1/3} × 60}/ {30 ×{2/3}}$ = 32 men

Hence, 32 men will be required to complete remaining work.