(i) Eight doctors P, Q, R, S, T, U, V and W visit a charitable dispensary every day except on a holiday i.e. Monday.

(ii) Each doctor visits for one hour from Tuesday and Sunday except Saturday. The timings are 9 a.m. to 1 p.m. and 2 p.m. to 6 p.m.; 1 p.m. to 2 p.m. is lunch break.

(iii) On Saturday, it is open only in the morning i.e. 9 a.m. to 1 p.m. and each doctor visits for only half an hour.

(iv) No other doctor visits the dispensary before doctor Q and after doctor U.

(v) Doctor W comes immediately after lunch break and is followed by R.

(vi) S comes in the same order as P in the afternoon session.

At what time the visit of Doctor T whould be over on Saturday ?

** Option:**

**A.**10 a.m.

**B.**11 a.m.

**C.**Either 10 a.m. or 11 a.m.

**D.**Data inadequate

**E.**None of these

**Answer: C . Either 10 a.m. or 11 a.m.**

** Justification:**

We first form the sequence of visit using (iv), (v) and (vi).

From (iv), we know that Q visits first and U visits last.

From (v), we know that W visits first after break and is followed by R.

From (vi), we know that P visits after break.

Thus, the sequence of visit after break becomes W R P U.

Also, S has the same position in morning session as P in afternoon session. So, sequence of visit before break is Q, T / V, S, V / T.

Clearly, T visits either second or fourth. So, the time of visit on Saturday will be either 9.30 a.m. or 10.30 a.m.

Thus, T's visit will be over at either 10 a.m. or 11 a.m.