In this type of questions, some clues are given regarding the order of occurrence of certain events. The candidate is required to analyse the given information, frame the right sequence and then answer the questions accordingly.
(i) Eight doctors P, Q, R, S, T, U, V and W visit a charitable dispensary every day except on a holiday i.e. Monday.
(ii) Each doctor visits for one hour from Tuesday and Sunday except Saturday. The timings are 9 a.m. to 1 p.m. and 2 p.m. to 6 p.m.; 1 p.m. to 2 p.m. is lunch break.
(iii) On Saturday, it is open only in the morning i.e. 9 a.m. to 1 p.m. and each doctor visits for only half an hour.
(iv) No other doctor visits the dispensary before doctor Q and after doctor U.
(v) Doctor W comes immediately after lunch break and is followed by R.
(vi) S comes in the same order as P in the afternoon session.
If the lunch break and subsequent visiting hours are reduced by 15 minutes, at what time Doctor U is excpected to attend the dispensary ?
We first form the sequence of visit using (iv), (v) and (vi).
From (iv), we know that Q visits first and U visits last.
From (v), we know that W visits first after break and is followed by R.
From (vi), we know that P visits after break.
Thus, the sequence of visit after break becomes W R P U.
Also, S has the same position in morning session as P in afternoon session. So, sequence of visit before break is Q, T / V, S, V / T.
Clearly, as mentioned, lunch break will be over and doctor W will visit at 1.45 p.m., doctor R will visit at 2.30 p.m., doctor P will visit at 3.15 p.m. and U will visit at 4 p.m.