If park with the length of 60 meter and width of 40 meter has two concrete crossroads in the middle and the remaining area is covered with the lawn, which area is 2109 Sq. meter, then what could be the width of the road?
A. 1 meter
B. 2 meter
C. 3 meter
D. 4 meter
Answer: C . 3 meterTweet
The area od the park is 60 * 40 = 2400 Sq. meter.
The lawn area is 2109 Sq. meter, so the road area is = 2400 - 2109 = 291 Sq. meter.
The road area = Park length * road Width + Park width * road width - overlapping road area
=> 60 * x + 40 * x - x^2 = 291
=> x^2 - 100x + 291 = 0
=> X^2 - 97x - 3x - 291 = 0
=> (x-97) * (x-3) = 0
Here, the roads are inside the park, so the width can't be 97 meter, so the width of the road is 3 meter.