If a man reduces his speed to 2/3, he takes 1 hour more in walking a certain distance.
The time (in hours) to cover the distance with his normal speed is :
Option:
A. 2
B. 1
C. 3
D. 1.5
Answer: A . 2
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Justification:
Suppose man covers x km in y hours.
His normal speed = x/y km/hr
Reduced speed = 2x/3y km/hr.
Time taken to cover x km = x/2x / 3y hrs
= 3y/2 hrs.
By hypothesis,
= 3/2y = y + 1
or
y = 2hrs
