If a man reduces his speed to 2/3, he takes 1 hour more in walking a certain distance.

The time (in hours) to cover the distance with his normal speed is :

** Option:**

**A.**2

**B.**1

**C.**3

**D.**1.5

**Answer: A . 2**

** Justification:**

Suppose man covers x km in y hours.

His normal speed = ^{x}/_{y} km/hr

Reduced speed = ^{2x}/_{3y }km/hr.

Time taken to cover x km = ^{x}/_{2x / 3y }hrs

= ^{3y}/_{2} hrs.

By hypothesis,

= ^{3}/_{2}y = y + 1

or

y = 2hrs