A blacksmith has five iron articles A, B, C, D and E, each having a different weight.
(i) A weights twice as much as B.
(ii) B weights four and a half times as much as C.
(iii) C weights half as much as D.
(iv) D weights half as much as E.
(v) E weights less than A but more than C.
E is lighter in weight than which of the other two articles ?
Let C's weight be x.
Then, D's weight is 2x. E's weight is 4x. B's weight is 4.5x and A's weight is 9x.
So, the order of weights can be A > B > E > D > C.
E is lighter in weight than A and B.