The system of equtions 3x + y - 1 = 0 and 6x + 2y - 2 = 0 - Linear Equations - Analogy - Verbal Reas

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The system of equtions 3x + y - 1 = 0 and 6x + 2y - 2 = 0

A. has x = 1 and y = 2 as solutions

B. has x = -1 and y = -2 as solutions

C. does not have a solution

D. has infinitely many solutions

E. None of the above

Answer: D. has infinitely many solutions

The given equations are 3x + y - 1 = 0 and 6x + 2y - 2 = 0.
So,
Equation I = (3x + y = 1) and
Equation II = (6x + 2y = 2)
= { 2(3x + y) = 2}
= 3x + y = 2/2
= 3x + y = 1
So, The given equations are 3x + y = 1 and 3x + y = 1.
Thus, there is one equation in two variables.
So, the given equations have an infinite number of solutions.

Posted in: Linear Equations - Analogy - Verbal Reasoning