The system of equtions 3x + y - 1 = 0 and 6x + 2y - 2 = 0

** Option:**

**A.**has x = 1 and y = 2 as solutions

**B.**has x = -1 and y = -2 as solutions

**C.**does not have a solution

**D.**has infinitely many solutions

**Answer: D . has infinitely many solutions**

** Justification:**

The given equations are 3x + y - 1 = 0 and 6x + 2y - 2 = 0.

So,

Equation I = (3x + y = 1) and

Equation II = (6x + 2y = 2)

= { 2(3x + y) = 2}

= 3x + y = 2/2

= 3x + y = 1

So, The given equations are 3x + y = 1 and 3x + y = 1.

Thus, there is one equation in two variables.

So, the given equations have an infinite number of solutions.