The equations 3x - 4y = 5 and 12x - 16y = 20 have :

** Option:**

**A.**no common solution.

**B.**exactly one common solution.

**C.**exactly two common solutions.

**D.**more than two common solutions.

**Answer: D . more than two common solutions.**

** Justification:**

The given equations are 3x - 4y = 5 and 12x - 6y = 20.

So, (12x - 16y = 20) = { 4(3x - 4y) = 4(5)} = 3x - 4y = 5.

So, The given equations are 3x - 4y = 5 and 3x - 4y = 5.

Thus, there is one equation in two variables.

So, the given equations have an infinite number of solutions.

Hence, the answer is (d).