What will be the decreased percent of the area of the circle, if the radius is decreased by 50%?
Answer: C . 75%Tweet
If the radius of the circle is = r, then the area A = Pi*r*r
If the radius is decreased by 50%, so the new radius is = r/2, so the area a = pi*r*r/2*2 = A/4
So, the difference (of percent) of the area is = ((A-A/4) / A) * 100% = 3/4*100% = 75%